How to Calculate the Surface Area of a Revolution

By Business & Finance Last updated Sunday, January/05/2025

1). Square the moving object's orbital velocity. With this example, imagine a satellite that moves at 3,080 meters per second: 3,080² = 9,486,400 m²/s².
2). Divide this answer by the mass of the body around which the object revolves. If it revolves around the earth, which has a mass of 5.97 --- 10^24 kg: 9,486,400 ÷ (5.97 --- 10^24) = 1.589 --- 10^-18 m²/s²kg.
3). Divide the universal gravitational constant, which is 6.674 --- 10^-11 m³/s²kg, by this answer: (6.674 --- 10^-11) ÷ (1.589 --- 10^-18) = 42,001,258.7 m. This is the radius of the object's orbit.
4). Square this radius: 42,001,258.7² = 1.764 --- 10^15 m³.
5). Multiply this answer by pi, which is approximately 3.142: (1.764 --- 10^15) --- 3.142 = 5.539 --- 10^15 m². Assuming a circular orbit, this is the surface area of the object's orbital plane.

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